python开发冒泡排序实方案
python开发冒泡排序实方案。
# -*- coding: utf_8 -*-
print(__doc__)
dic = {}
with open('G:/py_proj/test/flask.txt') as f:
for char in f.read().replace(' ',''):
if char in dic:
dic[char] += 1
else:
dic[char] = 1
# print(dic)
rev_list = list(dic.items())
length = len(rev_list)
# 冒泡排序
for i in range(length-1):
for j in range(length-i-1): #j为下标识
if rev_list[j][1] > rev_list[j+1][1]:
rev_list[j],rev_list[j+1] = rev_list[j+1],rev_list[j]
print(rev_list)
for char ,c in sorted(rev_list,key= lambda x:x[1],reverse= True):
print('%s count is %d' %(char,c))
相关文章
图文推荐
- 文章
- 推荐
- 热门新闻