[编程题]求最大值

[编程题] 最大和
在一个N*N的数组中寻找所有横，竖，左上到右下，右上到左下，四种方向的直线连续D个数字的和里面最大的值
输入描述:
每个测试输入包含1个测试用例，第一行包括两个整数 N 和 D :
3 <= N <= 100
1 <= D <= N
接下来有N行，每行N个数字d:
0 <= d <= 100

输出描述:
输出一个整数，表示找到的和的最大值

输入例子:
4 2
87 98 79 61
10 27 95 70
20 64 73 29
71 65 15 0

输出例子:
193
代码

#include 
#include 

using namespace std;

int main(void)
{
    int row, num;
    cin >> row >> num;
    int input[100][100];
   /* if (num > row)
    {
        return 0;
    }
    else
    {
        int sum = row*row;
        int **input = (int**)malloc(row*sizeof(int*));
        for (int i = 0; i < row; i++)
        {
            input[i] = new int[row];
            for (int j = 0; j < row; j++)
            {
                int cur;
                cin >> cur;
                input[i][j] = cur;
            }
        }
        */
    for(int i = 0;i>d;
            input[i][j]=d;
        }
    }
        int maxsum = -1;
        int rownum, colnum, cnt, pos, cursum;
        //所有水平方向的和
        for (rownum = 0; rownum < row; rownum++)
        {
            for (colnum = 0; colnum <= row - num; colnum++)
            {
                cnt = num;
                pos = colnum;
                cursum = 0;
                for (; cnt>0; cnt--)
                {
                    cursum += input[rownum][pos];
                    pos++;
                }
                if (cursum > maxsum)
                    maxsum = cursum;
            }
        }
        //所有垂直方向的和
        for (colnum = 0; colnum < row; colnum++)//每一列
        {
            for (rownum = 0; rownum <= row - num; rownum++)
            {
                cnt = num;
                pos = rownum;
                cursum = 0;
                for (; cnt>0; cnt--)
                {
                    cursum += input[pos][colnum];
                    pos++;
                }
                if (cursum > maxsum)
                    maxsum = cursum;
            }
        }
        //所有主对角线的和
        for (rownum = 0; rownum <= row - num; rownum++)
        {
            for (colnum = 0; colnum < row - num; colnum++)
            {
                cnt = num;
                pos = 0;
                cursum = 0;
                for (; cnt>0; cnt--)
                {
                    cursum += input[rownum + pos][colnum + pos];
                    pos++;
                }
                if (cursum > maxsum)
                    maxsum = cursum;
            }
        }
        //所有次对角线的和
        for (rownum = 0; rownum <= row - num; rownum++)
        {
            for (colnum = num - 1; colnum < row; colnum++)
            {
                cnt = num;
                pos = 0;
                cursum = 0;
                for (; cnt>0; cnt--)
                {
                    cursum += input[rownum + pos][colnum - pos];
                    pos++;
                }
                if (cursum > maxsum)
                    maxsum = cursum;
            }
        }
        cout << maxsum;
        return 0;
    //}
    //return 0;
}

您的代码已保存
答案错误:您提交的程序没有通过所有的测试用例
case通过率为98.00%

测试用例:
23 14

对应输出应该为:

1017

你的输出为:

986